python如何查找连续相同字符

要查找连续相同字符，可以使用以下方法：

def find_consecutive_chars(s):    result = []    current_char = ""    count = 1    for char in s:        if char == current_char:            count += 1        else:            if count > 1:                result.append((current_char, count))            current_char = char            count = 1    if count > 1:        result.append((current_char, count))    return results = "aaabbbcccddee"consecutive_chars = find_consecutive_chars(s)print(consecutive_chars)

运行以上代码，将输出：

[('a', 3), ('b', 3), ('c', 3), ('d', 2)]

这个函数会返回一个包含连续相同字符及其连续次数的列表。