C语言如何处理复数的浮点运算

在C语言中，可以使用结构体来表示复数，并定义相应的运算函数来处理复数的浮点运算。以下是一个简单的示例代码：

#include <stdio.h>typedef struct {    double real;    double imag;} Complex;Complex add(Complex c1, Complex c2) {    Complex result;    result.real = c1.real + c2.real;    result.imag = c1.imag + c2.imag;    return result;}Complex subtract(Complex c1, Complex c2) {    Complex result;    result.real = c1.real - c2.real;    result.imag = c1.imag - c2.imag;    return result;}Complex multiply(Complex c1, Complex c2) {    Complex result;    result.real = c1.real * c2.real - c1.imag * c2.imag;    result.imag = c1.real * c2.imag + c1.imag * c2.real;    return result;}void printComplex(Complex c) {    printf("%.2f + %.2fi\n", c.real, c.imag);}int main() {    Complex c1 = {3.0, 4.0};    Complex c2 = {1.0, 2.0};    Complex sum = add(c1, c2);    Complex difference = subtract(c1, c2);    Complex product = multiply(c1, c2);    printf("Sum: ");    printComplex(sum);    printf("Difference: ");    printComplex(difference);    printf("Product: ");    printComplex(product);    return 0;}

在上面的代码中，定义了一个Complex结构体来表示复数，然后定义了三个函数来实现复数的加法、减法和乘法运算。在main函数中，创建了两个复数c1和c2，并调用相应的函数来进行运算，并输出结果。